697A - Pineapple Incident - CodeForces Solution

implementation math *900

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Python Code: 

t, s, x = (int(i) for i in input().split())

if x < t:
    print('NO')
else:
    print(('NO', 'YES')[(x - t) % s == 0 or (x - 1 != t and (x - t - 1) % s == 0)])

C++ Code: 

#include<bits/stdc++.h>
using namespace std;
#define aa() ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define endl '\n'
int main()
{
    aa();
    long long a,b,c;
    cin>>a>>b>>c;
    if(a>c)cout<<"NO"<<endl;
    else if(a==c)cout<<"YES"<<endl;
    else
    {
        bool flag=0;
        long long d=0;
        long long x=a;
        while(x<=c)
        {
            d++;
            if((a+(d*b))==c ||(a+(d*b)+1)==c)
            {
                flag=1;
                break;
            }
            x=a+(d*b);
        }
        if(flag)cout<<"YES"<<endl;
        else cout<<"NO"<<endl;
    }
}


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